Ballupur Dehradun, Dehradun, India - 248001.
Details verified of Ankit Chauhan✕
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Hindi Mother Tongue (Native)
College of Engineering Roorkee 2018
Bachelor of Technology (B.Tech.)
Ballupur Dehradun, Dehradun, India - 248001
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Quantitative Aptitude Coaching
1
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
NIOS Subjects taught
Science, Mathematics
Board
CBSE, NIOS, ICSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Mathematics, Physics
Experience in School or College
I have an experience to teach technical subjects .
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BSc Tuition
1
BSc Electronics Subjects
Digital Electronics, Engineering Mathematics, Signals and Systems, Mathematics, Analog Electronics
Experience in School or College
I have 2year experience as a mentor .
Type of class
Crash Course, Regular Classes
Class strength catered to
Group Classes
Taught in School or College
Yes
BSc Branch
BSc Mathematics, BSc Electronics
BSc Mathematics Subjects
Calculus, Algebra, Differential Equations and Mathematical Modelling
1. Which classes do you teach?
I teach BSc Tuition, Class 10 Tuition, Engineering Entrance Coaching and Quantitative Aptitude Classes.
2. Do you provide a demo class?
Yes, I provide a free demo class.
3. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 28/08/2020 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Advanced Coaching
It is because when you insert a resistor, or when a conductor (resistors are conductors) is connected to a voltage source such as a battery, the negative terminal will present an opposing electrostatic force the conductor as well as have a ready supply of additional electrons. This field will repel electrons in the conductor and exert a force on them and will attempt to inject fresh electrons into the conductor. At the opposite end, where the conductor is connected to the positive terminal of the voltage source, a force exists to pull electrons from the conductor.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Quantitative Aptitude Coaching
1
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
NIOS Subjects taught
Science, Mathematics
Board
CBSE, NIOS, ICSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Mathematics, Physics
Experience in School or College
I have an experience to teach technical subjects .
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BSc Tuition
1
BSc Electronics Subjects
Digital Electronics, Engineering Mathematics, Signals and Systems, Mathematics, Analog Electronics
Experience in School or College
I have 2year experience as a mentor .
Type of class
Crash Course, Regular Classes
Class strength catered to
Group Classes
Taught in School or College
Yes
BSc Branch
BSc Mathematics, BSc Electronics
BSc Mathematics Subjects
Calculus, Algebra, Differential Equations and Mathematical Modelling
Answered on 28/08/2020 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Advanced Coaching
It is because when you insert a resistor, or when a conductor (resistors are conductors) is connected to a voltage source such as a battery, the negative terminal will present an opposing electrostatic force the conductor as well as have a ready supply of additional electrons. This field will repel electrons in the conductor and exert a force on them and will attempt to inject fresh electrons into the conductor. At the opposite end, where the conductor is connected to the positive terminal of the voltage source, a force exists to pull electrons from the conductor.
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