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Class 12 Tuition > Class 12 Tuition in Vadavalli > Balasubramanian G

Balasubramanian G Class 12 Tuition trainer in Coimbatore

Balasubramanian G

Mathematics Tutor

Marudhamalai Rd Coimbatore, Vadavalli, India - 641041.

Verified 11 Students

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I am a post graduate in Mathematics and am passionate about teaching Mathematics.
I teach Mathematics for students of Classes 9th to 12th in ENGLISH MEDIUM. I teach both the syllabi - CBSE and State
My strength is in teaching the fundamental concepts clearly to the students to enable them to understand the different techniques of problem solving.
Currently I am taking online and home tuitions in Mathematics to 8 students in X to XII standards in both CBSE and State syllabus.
I have about 3 years of experience in teaching Mathematics.
I have a master's degree in Computer Applications too.
I take only minimum number of students every year and coach them, so that I can give individual attention to each and every student.

Languages Spoken

Tamil

English

Hindi Basic

Education

University of Madras 1975

Master of Science (M.Sc.)

Bharathiar University, Coimbatore 1999

Master of Computer Applications (M.C.A.)

Address

Marudhamalai Rd Coimbatore, Vadavalli, India - 641041

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Teaches

Class 12 Tuition
3 Students

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

3

Board

CBSE, State

CBSE Subjects taught

Mathematics, Computer Science

Taught in School or College

No

State Syllabus Subjects taught

Computer Science, Mathematics

Class 10 Tuition
2 Students

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

3

Board

CBSE, State

CBSE Subjects taught

Mathematics, Computer Science

Taught in School or College

No

State Syllabus Subjects taught

Computer Science, Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

CBSE, State

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 3 years.

Contact

Answers by Balasubramanian G (4)

Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Coordinate geometry/NCERT Solutions/Exercise 7.2

Find the coordinates of the points of trisection of the line segment joining (4, –1) and (–2, –3).

(2, -5/3) (0, -7/3)
Answers 3 Comments
Dislike Bookmark

Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Polynomials/NCERT Solutions/Exercise 2.1

The graphs of y=p(x) are given below for some polynomials p(x). Find the numbers of zeros of p(x) in... ...more

The graphs of y=p(x) are given below for some polynomials p(x). Find the numbers of zeros of p(x) in each case.

(i) 0 (iii) 3 (ii) 1. (iv). 2 (v) 4 (vi) 3
Answers 21 Comments
Dislike Bookmark

Answered on 12/01/2018 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

If a coin is tossed for a certain number of times. How many times the coin was tossed, if the probability... ...more
If a coin is tossed for a certain number of times. How many times the coin was tossed, if the probability of getting a head is 0.4 and it appeared up for 24 times?

Probability of an event = No. Of favourable occurrences / Total no. Of occurrences of all possible events Let 'n' be the total no. Of times the coin is tossed. Given probability of success of a head appearing = 0.4 Given the no. Of times 'head' appeared = 24 So, 0.4 = 24 / n n = 24 / 0.4 So, n = 60. ...more

Probability of an event = No. Of favourable occurrences / Total no. Of occurrences of all possible events

Let 'n' be the total no. Of times the coin is tossed.

Given probability of success of a head appearing = 0.4

Given the no. Of times 'head' appeared = 24

So, 0.4 = 24 / n

n = 24 / 0.4

So, n = 60.

Answers 9 Comments
Dislike Bookmark

Answered on 09/01/2018 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

The exterior angles obtained on producing the base of a triangle both ways are 100° and 120°. Find all the angles.

Let A, B and C be the vertices of the triangle with B and C as the base vertices. If the external angle at C is 100 degrees then the angle C is 80 degrees (because sum of adjacent angles on a straight line is 180 degrees). Similarly if the external angle at B is 120 degrees then the angle B is 60 degrees.... ...more

Let A, B and C be the vertices of the triangle with B and C as the base vertices. If the external angle at C is 100 degrees then the angle C is 80 degrees (because sum of adjacent angles on a straight line is 180 degrees). Similarly if the external angle at B is 120 degrees then the angle B is 60 degrees. So the angle A is 40 degrees. i.e. 180 - (80 + 60).

Answers 6 Comments
Dislike Bookmark

Contact

Teaches

Class 12 Tuition
3 Students

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

3

Board

CBSE, State

CBSE Subjects taught

Mathematics, Computer Science

Taught in School or College

No

State Syllabus Subjects taught

Computer Science, Mathematics

Class 10 Tuition
2 Students

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

3

Board

CBSE, State

CBSE Subjects taught

Mathematics, Computer Science

Taught in School or College

No

State Syllabus Subjects taught

Computer Science, Mathematics

No Reviews yet!

Answers by Balasubramanian G (4)

Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Coordinate geometry/NCERT Solutions/Exercise 7.2

Find the coordinates of the points of trisection of the line segment joining (4, –1) and (–2, –3).

(2, -5/3) (0, -7/3)
Answers 3 Comments
Dislike Bookmark

Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Polynomials/NCERT Solutions/Exercise 2.1

The graphs of y=p(x) are given below for some polynomials p(x). Find the numbers of zeros of p(x) in... ...more

The graphs of y=p(x) are given below for some polynomials p(x). Find the numbers of zeros of p(x) in each case.

(i) 0 (iii) 3 (ii) 1. (iv). 2 (v) 4 (vi) 3
Answers 21 Comments
Dislike Bookmark

Answered on 12/01/2018 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

If a coin is tossed for a certain number of times. How many times the coin was tossed, if the probability... ...more
If a coin is tossed for a certain number of times. How many times the coin was tossed, if the probability of getting a head is 0.4 and it appeared up for 24 times?

Probability of an event = No. Of favourable occurrences / Total no. Of occurrences of all possible events Let 'n' be the total no. Of times the coin is tossed. Given probability of success of a head appearing = 0.4 Given the no. Of times 'head' appeared = 24 So, 0.4 = 24 / n n = 24 / 0.4 So, n = 60. ...more

Probability of an event = No. Of favourable occurrences / Total no. Of occurrences of all possible events

Let 'n' be the total no. Of times the coin is tossed.

Given probability of success of a head appearing = 0.4

Given the no. Of times 'head' appeared = 24

So, 0.4 = 24 / n

n = 24 / 0.4

So, n = 60.

Answers 9 Comments
Dislike Bookmark

Answered on 09/01/2018 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

The exterior angles obtained on producing the base of a triangle both ways are 100° and 120°. Find all the angles.

Let A, B and C be the vertices of the triangle with B and C as the base vertices. If the external angle at C is 100 degrees then the angle C is 80 degrees (because sum of adjacent angles on a straight line is 180 degrees). Similarly if the external angle at B is 120 degrees then the angle B is 60 degrees.... ...more

Let A, B and C be the vertices of the triangle with B and C as the base vertices. If the external angle at C is 100 degrees then the angle C is 80 degrees (because sum of adjacent angles on a straight line is 180 degrees). Similarly if the external angle at B is 120 degrees then the angle B is 60 degrees. So the angle A is 40 degrees. i.e. 180 - (80 + 60).

Answers 6 Comments
Dislike Bookmark

Contact

Balasubramanian G describes himself as Mathematics Tutor. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Balasubramanian is located in Marudhamalai Rd Coimbatore, Coimbatore. Balasubramanian takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 3 years of teaching experience . Balasubramanian has completed Master of Science (M.Sc.) from University of Madras in 1975 and Master of Computer Applications (M.C.A.) from Bharathiar University, Coimbatore in 1999. He is well versed in Tamil, Hindi and English.

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