when the pH of a saturated solution of M(OH)2 is 13. Hence Ksp of M(OH)2 is

Asked by Last Modified  

14 Answers

Learn Class XI-XII Tuition (PUC)

Follow 12
Answer

Please enter your answer

POH = 1 2OH = 10^-1 OH = 0.05 M s = 0.05 M Ksp = 4s^3 Ksp = 5 x 10^-4 M^3
Comments
Dislike Bookmark

Tutor

M(OH)2 gives M+(ion) + 2 (OH)- ions. So concentration of M+ ion is half that of OH- ions. To calculate the concentration of OH minus ions we need pOH value which is equal to {14 - pH}. In this question pH is 13 therefore pOH = 1. Concentration of OH ions is given by = 10^ (-pOH). ...
read more
M(OH)2 gives M+(ion) + 2 (OH)- ions. So concentration of M+ ion is half that of OH- ions. To calculate the concentration of OH minus ions we need pOH value which is equal to {14 - pH}. In this question pH is 13 therefore pOH = 1. Concentration of OH ions is given by [OH] = 10^ (-pOH). = 10^-1 =0.1 M (here M is molarity, mol/l) To calculate concentration of metal ion namely [M] is half of the concentration of OH ion =(0.1)/2 =0.05 M once we have concentration of these let us now calculate the Ksp value. Ksp for this = [M] * [OH]^2 = 0.05 * (0.1)^2 =0.0005 = 5* !0^(-4) units will be M^3 read less
Comments
Dislike Bookmark

IIT qualified chemist

0.004
Comments
Dislike Bookmark

Chemistry expert

pH=13 pOH=1 =0.1 =2S Ksp=4s3=5 X 10-4
Comments
Dislike Bookmark

Teacher

pH value = 13 , pOH = 14-13 = 1 , = 10-1 = 0.1 , = 0.1/2 = 0.05 , Ksp = 2 = (0.05)2(0.1) Ksp = 0.0025 x 0.1 = 2.5x10-4
Comments
Dislike Bookmark

Teacher

pH = 13 , pOH = 14-13 = 1 , = 10-1 = 0.1 , = 0.1/2 = 0.05 Ksp = 2 = 0.1 x (.05)2 = 0.1x0.0025 = 2.5x10-4
Comments
Dislike Bookmark

IIT/BITSAT Decoded !!

Hi K.kamal Here is the solution to your problem: M(OH)2 ---> M2+ + 2OH- (1) Ksp = X^2 (2) Now concentration of OH- can be calculated as pOH+PH =14 at 25C taken as standard. therefore POH=1 { ph=13 given } hence OH- =10^-1 Now conc. of M2+ will be half...
read more
Hi K.kamal Here is the solution to your problem: M(OH)2 ---> M2+ + 2OH- (1) Ksp = [M2+]X[OH-]^2 (2) Now concentration of OH- can be calculated as pOH+PH =14 at 25C taken as standard. therefore POH=1 { ph=13 given } hence OH- =10^-1 Now conc. of M2+ will be half the conc. of OH- at equib. as it is clear from above equation(1) therefore putting values in (2) Ksp= (0.5x10^-1)x(10^-1)^2 = 0.5x10^-3 mol^3litre^-3 read less
Comments
Dislike Bookmark

Professional Chemistry Teacher for IIT JEE/NEET UG,Online expert for IB/IGCSE/AP CURRICULUM

M(OH)2 is a base,so PH+POH=14 POH=1,=0.1Normal 2=0.1 =0.1/2=0.05normal For M(OH)2,Ksp=4SPower 3 Ksp=0.0005
Comments
Dislike Bookmark

Math Educator for Std.11th ,12th , Engineering Entrance and Degree Level with 11+ Years Experience

PLEASE GO THROUGH INSERT EQUATION OPTION IN MS WORD. YOU WILL GET MY ANSWER IN CLEAR FORMAT ?M(OH)?_2 ? M^(2+ )+ 2 ?OH?^- Ksp= ^2 P^H = 13 P^OH = 14 -- 13 = 1 = ?10?^(-P^OH...
read more
PLEASE GO THROUGH INSERT EQUATION OPTION IN MS WORD. YOU WILL GET MY ANSWER IN CLEAR FORMAT ?M(OH)?_2 ? M^(2+ )+ 2 ?OH?^- Ksp= [M^(2+) ] [?OH?^- ]^2 P^H = 13 P^OH = 14 – 13 = 1 [?OH?^- ] = ?10?^(-P^OH ) = ?10?^(-1) M [M^(2+) ]= ?10?^(-1)/2 = 5.0 × ?10?^(-2) Ksp=(5.0 × ?10?^(-2) )?(?10?^(-1))?2 Ksp of M(OH)2 is = 5.0 × 10^(-4) read less
Comments
Dislike Bookmark

MATH PHY CHEM TEACHER ONLY SANT NAGAR BURARI

We know the Ksp and we know the solution is saturated. This information will be sufficient.we must first calculate the . To do this, we will use the Ksp expression and then, at the end, we will use acid base concepts to get the pH. Ksp are almost always given at 25.0 °C in reference sources
Comments
Dislike Bookmark

View 12 more Answers

Related Questions

What advantages a life insurance policy can give?
Life Insurance is a policy which will safeguard financial interest of your immediate family members (nominee) in case of any untoward incident (like death of yours). Secondly, it is also used as reducing your tax liability.
Archit
0 0
8
How many districts in Haryana at present?
21
Rajat
What is least integer function Difference between greatest integer function and least integer function
contact us for more details
Vigyan
Is it right that in class 11 for science , we got 7.0 CGPA in class 10?
Firstly I would say that marks are of no importance when you come up to the real world above ur book.... it's just that .... if you are interested in something ... and you really want to explore ur favourite...
Vanshika jindal
A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively? A. 2 : 1 B. 3 : 2 C. 8 : 3 D. Cannot be determined
Let the man's rate upstream be x kmph and that downstream be y kmph. Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs. x x 8 4 = (y x 4) 5 44 x =4y 5 ...
Srikanth
0 0
7

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Halegannada padagala artha - 1

Sandhya

0 0
0
Chapter 10: Cell Cycle & Cell Division (Class XI- NCERT)
CH 10 Cell Cycle & Cell Division: The Cell Cycle: The cell cycle is a series of sequential events that result in duplication and equal distribution of DNA and other sub-cellular components of the...

Neeraj Kumar

0 0
0
Limits
As I have seen a common mistake done by the students, so I am going to explain what is this term is all about. Limit is the base of calculus which was introduced by Newton. The word 'Limit' states the...

Shikha

0 0
0
Magu matthu hannugalu - Shabdhartha

Sandhya

0 0
0
Fundamentals Of Partnership Test: 11th Classes
Q1. X and Y are partners sharing profits and losses in the ratio of 3: 2 with capitals of Rs. 50,000 and Rs. 30,000 respectively. Each partner is entitled to 6% interest on his capital. X is entitled to...

Vidyadhan Academy Pvt. Ltd.

0 0
0

Recommended Articles

Meet Radhe Shyam Burman, an MBA Tutor from...

Radhe Shyam is a highly skilled accounts and finance trainer with 8 years of experience in teaching. Accounting is challenging for many students and that’s where Radhe Shyam’s expertise comes into play. He helps his students not only in understanding the subject but also advises them on how to overcome the fear of accounts...

Read full article >

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Meet Urmila, an MBBS tutor from Bangalore

Urmila is a passionate teacher with over 8 years of experience in teaching. She is currently pursuing her Ph. D. She provides classes for Class 11, Class 12, MBBS and Medical tuition.  Urmila began her career in teaching long before she became a teacher. She used to provide classes for foreign national students in her college...

Read full article >

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Find Class 12 Tuition near you
Class 12 Tuition in Delhi
Class 12 Tuition in Bangalore
Class 12 Tuition in Hyderabad
Class 12 Tuition in Chennai
Class 12 Tuition in Mumbai
Class 12 Tuition in Kolkata
Class 12 Tuition in Pune
Class 12 Tuition in Jaipur
Class 12 Tuition in Noida
Class 12 Tuition in Lucknow
Online Tuition Class 12

Looking for Class 12 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you