I have a maths. question from the Class XII Mathematics book by R.D.Sharma ( Chapter Complex numbers ) . I request anyone who can solve the problem step by step and send me the same The problem is as under : Locate the region represented by the complex number z in the Argand plane in case of the following condition : log((pi/6),((|z-2|+5)/(4*|z-2|-4)))<2. Please send step by step solution for the above question. Regards, S.B.Roy

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I reckon that Mr. Bhushan did a typo error and the original problem is something like this, Located the region represented by the complex number z in the Argand plane in case of the following condition : log(pi/6) < (|z-2| + 5) / (4*|z-2| - 4) < 2 The detailed solution as requested...
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I reckon that Mr. Bhushan did a typo error and the original problem is something like this, Located the region represented by the complex number z in the Argand plane in case of the following condition : log(pi/6) < (|z-2| + 5) / (4*|z-2| - 4) < 2 The detailed solution as requested by you is as follows: |z-2| + 5 log(pi/6) < --------------- < 2 4|z-2| - 4 |z-2| + 5 therefore 4 * log(pi/6) < ---------------------- < 8 |z-2| - 1 Writing 5 = -1+6, we get (|z-2| -1) + 6 4log(pi/6) < -------------------------- < 8 ( |z-2| -1 ) 6 4 log(pi/6) < 1 + --------------- < 8 |z-2| -1 6 4log(pi/6) - 1 < ------------------ < 7 |z-2| - 1 INVERTING THE INEQUALITY GIVES US 1 |z-2| - 1 1 ------- < ---------------- < ----------------------- 7 6 4log(pi/6) -1 6 6 ---------- < |z-2| -1 < ------------------------ 7 4log(pi/6) - 1 13 6 --------- < |z-2| < -------------------------- + 1 7 4log(pi/6) - 1 13 6 + 4log(pi/6) -1 -------- < |z-2| < ------------------------------ 7 4log(pi/6) - 1 But |z-2| = | x + yi -2| = | ( x - 2 ) + yi | = ( x - 2) ^2 + y ^2 is the equation of a circle, hence our problem becomes 13 5 + 4log(pi/6) -------- < ( x - 2) ^2 + y ^2 < ------------------------------ 7 4log(pi/6) - 1 Or, A < ( x - 2) ^2 + y ^2 < B with A and B corresponding to the above values i.e A = 13 / 7 and B = the complicated fraction on the right The above inequality can be interpreted as the region between two concentric circles centered at (2,0) with two different radii. Smaller circle with radius = square root (A) and centered at (2,0) and larger circle with radius = square root (B) and centered at (2,0). Your solution is the entire region between these two circles. My only concern is that log(pi/6) is essentially negative and I have no clue as to which base are you using to calculate log(pi/6). This has serious consequences if you know what I mean. I hope this is clear now. May I suggest Complex Variables by Churchill and Brown as a good book to learn more about complex variables. Cheers read less
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I'll go with Mr.Santosh
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Trainer

I support Santosh answer.
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log(pi/6)<2 log(22/7X6)<2 log(22/7X6)<2 log(22/42)<2 log(0.5238)<2 -0.2808<2
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Founder of Research Pathshala (Online Coaching)

Remove log by using laws of logarithm and then solve the inequality, keeping Z = a + ib. Now use the argand plane to show the results. If you can't figure it out...please stop solving and go back to brush up basics! From the question as asked it is not clear as symbols are not visible. Please study before...
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Remove log by using laws of logarithm and then solve the inequality, keeping Z = a + ib. Now use the argand plane to show the results. If you can't figure it out...please stop solving and go back to brush up basics! From the question as asked it is not clear as symbols are not visible. Please study before putting these cranky questions! read less
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Math Educator for Std.11th ,12th , Engineering Entrance and Degree Level with 11+ Years Experience

Your problem is missing some mathematical symbols. Please correct it.
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Maths, Physics & Science for free

WHAT IS AFTER PI/6, SEEMS COMMA SHOULD NOT BE THERE. PLEASE CORRECT
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Maths Pro

i think you should recheck the question
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Comprehensive Knowledge , well mix of basic and advanced concept , Industrial utility

do you have concept of this statement.. what will be the expected shape of region..
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Trainer

to place step wise solution for the above problem. Clarity also missing in that problem.
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