0Suppose there are two metallic charged bodies A and B, separated by an distance x and each having equal amount of charge, Q. Now another metallic uncharged body C is brought in contact with body A and then made contact with body B. Now body C is removed from B. What is the amount of charge left with A and B respectively.
Solution:-
- Initially body A and B have charge Q each.
- Where body A is made contact wth body C then charge present in body A gets halved due sharing with body C.
- Here we can see that total charge remains constant before and after contact, hence it proves law of conservation of charge.
- Body A and C carirreis charge Q/2 each due to sharing.
- Now body C is removed from A and made contact with body B.
- Here we can see that body B contains charge Q and body C contains charge Q/2.
- So total charege will be (Q+Q/2) = 3Q/2 and each body will have charge 3Q/4.
- Hence total chare left with body A and body B is Q/2 and 3Q/4 respectively.
