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Electrostatic charge distribution.

Aslam Mohammed
08/04/2017 0 0

Suppose there are two metallic charged bodies A and B, separated by an distance x and each having equal amount of charge, Q. Now another metallic uncharged body C is brought in contact with body A and then made contact with body B. Now body C is removed from B. What is the amount of charge left with A and B respectively.

Solution:-

  • Initially body A and B have charge Q each.
  • Where body A is made contact wth body C then charge present in body A gets halved due sharing with body C.
  • Here we can see that total charge remains constant before and after contact, hence it proves law of conservation of charge.
  • Body A and C carirreis charge Q/2 each due to sharing.
  • Now body C is removed from A and made contact with body B.
  • Here we can see that body B contains charge Q and body C contains charge Q/2.
  • So total charege will be (Q+Q/2) = 3Q/2 and each body will have charge 3Q/4.
  • Hence total chare left with body A and body B is Q/2 and 3Q/4 respectively.
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