A shell of mass 0.020kg is fired by a gun of mass 100kg. If the muzzle speed of the shell is 80m/s, what is the recoil speed of the gun?

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Sujoy Das

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Mass of the gun, M = 100 kg Mass of the shell, m = 0.020 kg Muzzle speed of the shell, v = 80 m/s Recoil speed of the gun = V Both the gun and the shell are at rest initially. Initial momentum of the system = 0 Final momentum of the system = mv â?? MV Here, the negative sign appears because the...
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Mass of the gun, M = 100 kg Mass of the shell, m = 0.020 kg Muzzle speed of the shell, v = 80 m/s Recoil speed of the gun = V Both the gun and the shell are at rest initially. Initial momentum of the system = 0 Final momentum of the system = mv â?? MV Here, the negative sign appears because the directions of the shell and the gun are opposite to each other. According to the law of conservation of momentum: Final momentum = Initial momentum mv â?? MV = 0 â?´ V = mv / M = 0.020 Ã? 80 / (100 Ã? 1000) = 0.016 m/s read less
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apply Newtons 3rd law of motion- Action = reaction Kinetic energy of sheel = Kinetic energy of gun 0.020*80*80/2 = 100*v*v/2 v = 1.13 metre/sec hence recoil speed of gun = 1.13 metre/sec
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Mass of the gun, M = 100 kg Mass of the shell, m = 0.020 kg Muzzle speed of the shell, v = 80 m/s Recoil speed of the gun = V Both the gun and the shell are at rest initially. Initial momentum of the system = 0 Final momentum of the system = mv â?? MV Here, the negative sign appears because...
read more
Mass of the gun, M = 100 kg Mass of the shell, m = 0.020 kg Muzzle speed of the shell, v = 80 m/s Recoil speed of the gun = V Both the gun and the shell are at rest initially. Initial momentum of the system = 0 Final momentum of the system = mv â?? MV Here, the negative sign appears because the directions of the shell and the gun are opposite to each other. According to the law of conservation of momentum: Final momentum = Initial momentum mv â?? MV = 0 â?´ V = mv / M = 0.020 Ã? 80 / (100 Ã? 1000) = 0.016 m/s read less
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SINGER CUM MATH MAGICIAN

here momentum is conserved..try m1v1=m2v2..this will give v2=0.016 m/s.
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By law of conservation of momentum, m1v1+m2v2=m1u1+m2u2 =>0.020Ã?80 +100Ã?v2=0 =>1.6+100v2=0 =>v2=-1.6/100=-0.016m/s
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