UrbanPro
true

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Application Of Trigonometry

Shuvham Singhal
29/07/2017 0 0

Solve the triangle shown below:

Applications of Right Triangle Trigonometry Example 1.svg

Solution:

We need to find the lengths of all sides and the measures of all angles. In this triangle, two of the three sides are given. We can find the length of the third side using the Pythagorean Theorem:

8 2 + b 2 = {\displaystyle 8^{2}+b^{2}=\,\!} 8^{2}+b^{2}=\,\! 10 2 {\displaystyle 10^{2}\,\!} 10^{2}\,\!
64 + b 2 = {\displaystyle 64+b^{2}=\,\!} 64+b^{2}=\,\! 100 {\displaystyle 100\,\!} 100\,\!
b 2 = {\displaystyle b^{2}=\,\!} b^{2}=\,\! 36 {\displaystyle 36\,\!} 36\,\!
b = {\displaystyle b=\,\!} b=\,\! ± 6 ⇒ b = 6 {\displaystyle \pm 6\Rightarrow b=6\,\!} \pm 6\Rightarrow b=6\,\!

(You may have also recognized the "Pythagorean Triple", 6, 8, 10, instead of carrying out the Pythagorean Theorem.)

You can also find the third side using a trigonometric ratio. Notice that the missing side, b, is adjacent to angle A, and the hypotenuse is given. Therefore we can use the cosine function to find the length of b:

cos ? ( 53.13 ? ) = {\displaystyle \cos(53.13^{\circ })=\,\!} \cos(53.13^{\circ })=\,\! adjacent side hypotenuse = b 10 {\displaystyle {\frac {\text{adjacent side}}{\text{hypotenuse}}}={\frac {b}{10}}} {\frac {{\text{adjacent side}}}{{\text{hypotenuse}}}}={\frac {b}{10}}
0.6 = {\displaystyle 0.6=\,\!} 0.6=\,\! b 10 {\displaystyle {\frac {b}{10}}} {\frac {b}{10}}
b = {\displaystyle b=\,\!} b=\,\! 0.6 ( 10 ) = 6 {\displaystyle 0.6(10)=6\,\!} 0.6(10)=6\,\!

We could also use the tangent function, as the opposite side was given. It may seem confusing that you can find the missing side in more than one way. The point is, however, not to create confusion, but to show that you must look at what information is missing, and choose a strategy. Overall, when you need to identify one side of the triangle, you can either use the Pythagorean Theorem, or you can use a trig ratio.

To solve the above triangle, we also have to identify the measures of all three angles. Two angles are given: 90 degrees and 53.13 degrees. We can find the third angle using the triangle angle sum:

180 − 90 − 53.13 = 36.87°

Solve the triangle shown below.

Applications of Right Triangle Trigonometry Example 2.svg

Solution: In this triangle, we need to find the lengths of two sides. We can find the length of one side using a trig ratio. Then we can find the length of the third side either using a trig ratio, or the Pythagorean Theorem.

We are given the measure of angle A, and the length of the side adjacent to angle A. If we want to find the length of the hypotenuse, c, we can use the cosine ratio:

cos ? ( 40 ? ) = {\displaystyle \cos(40^{\circ })=\,\!} \cos(40^{\circ })=\,\! adjacent hypotenuse = 6 c {\displaystyle {\frac {\text{adjacent}}{\text{hypotenuse}}}={\frac {6}{c}}} {\frac {{\text{adjacent}}}{{\text{hypotenuse}}}}={\frac {6}{c}}
cos ? ( 40 ? ) = {\displaystyle \cos(40^{\circ })=\,\!} \cos(40^{\circ })=\,\! 6 c {\displaystyle {\frac {6}{c}}} {\frac {6}{c}}
c cos ? ( 40 ? ) = {\displaystyle c\cos(40^{\circ })=\,\!} c\cos(40^{\circ })=\,\! 6 {\displaystyle 6\,\!} 6\,\!
c = {\displaystyle c=\,\!} c=\,\! 6 cos ? ( 40 ? ) ≈ 7.83 {\displaystyle {\frac {6}{\cos(40^{\circ })}}\approx 7.83} {\frac {6}{\cos(40^{\circ })}}\approx 7.83

If we want to find the length of the other leg of the triangle, we can use the tangent ratio. (Why is this a better idea than to use the sine?)

tan ? ( 40 ? ) = {\displaystyle \tan(40^{\circ })=\,\!} \tan(40^{\circ })=\,\! opposite adjacent = a 6 {\displaystyle {\frac {\text{opposite}}{\text{adjacent}}}={\frac {a}{6}}} {\frac {{\text{opposite}}}{{\text{adjacent}}}}={\frac {a}{6}}
tan ? ( 40 ? ) = {\displaystyle \tan(40^{\circ })=\,\!} \tan(40^{\circ })=\,\! a c {\displaystyle {\frac {a}{c}}} {\frac {a}{c}}
a = {\displaystyle a=\,\!} a=\,\! 6 tan ? ( 40 ? ) ≈ 5.03 {\displaystyle 6\tan(40^{\circ })\approx 5.03\,\!} 6\tan(40^{\circ })\approx 5.03\,\!

Now we know the lengths of all three sides of this triangle. In the review questions, you will verify the values of c and a using the Pythagorean Theorem. Here, to finish solving the triangle, we only need to find the measure of angle B:

180 − 90 − 40 = 50°
0 Dislike
Follow 0

Please Enter a comment

Submit

Other Lessons for You

Ways to Learn Faster, Deeper, and Better Health
Shake a leg. Lack of blood flow is a common reason for lack of concentration. If you’ve been sitting in one place for awhile, bounce one of your legs for a minute or two. It gets your blood flowing...

Squaring numbers ending in 5..
Solve the square of 25, in a jiffy. Answer : 625 Another one: square of 35. Answer : 1225. How it is done ?25 x 25 . The last two digits of the product will always be 25 ( as 5 x 5 =25). The initial...

Oxidative Phosphorylation
Oxidative PhosphorylationIt is the main source of energy of our cell. Takes place in Mitochondria. Movement of protons through inner mitochondrial membrane leads to ATP production. Definition:Oxidative...

Basic Percentage Review short cut tricks
So what is the easiest way to calculate percentages? Here are some tips to quickly find percentages mentally. Think like this: There are some percentages that are easy to calculate mentally. 50% means...

Indices of Numbers
Squares and Cubes from Numbers 1 to 100: NUMBER SQUARE CUBE X X2 X3 1 1 1 2 4 8 3 9 27 4 16 64 5 25 125 6 36 216 7 49 343 8 64 512 9 81 729 10 100 1000 11 121 1331 12 144 1728 13 169 2197 14 196 2744 15 225 3375 16 256 4096 17 289 4913 18 324 5832 19 361 6859 20 400 8000 21 441 9261 22 484 10648 23 529 12167 24 576 13824 25 625 15625 26 676 17576 27 729 19683 28 784 21952 29 841 24389 30 900 27000 31 961 29791 32 1024 32768 33 1089 35937 34 1156 39304 35 1225 42875 36 1296 46656 37 1369 50653 38 1444 54872 39 1521 59319 40 1600 64000 41 1681 68921 42 1764 74088 43 1849 79507 44 1936 85184 45 2025 91125 46 2116 97336 47 2209 103823 48 2304 110592 49 2401 117649 50 2500 125000 51 2601 132651 52 2704 140608 53 2809 148877 54 2916 157464 55 3025 166375 56 3136 175616 57 3249 185193 58 3364 195112 59 3481 205379 60 3600 216000 61 3721 226981 62 3844 238328 63 3969 250047 64 4096 262144 65 4225 274625 66 4356 287496 67 4489 300763 68
X

Looking for Class 10 Tuition Classes?

The best tutors for Class 10 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 10 Tuition with the Best Tutors

The best Tutors for Class 10 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more