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Using appropriate properties find:

(i) 

(ii) 

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(i) (ii) (By commutativity)
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(i)

(ii)

(By commutativity)

 

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Engineering graduate from NIT Calicut, Rank holder (#47) in State Entrance Examination.

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Engineering graduate from NIT Calicut, Rank holder (#47) in State Entrance Examination.

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Commutative then use distributivity properties
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Commutative then use distributivity properties
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(i) -2/3 × 3/5 - 3/5 ×1/6 + 5/2 = (-2/3) × 3/5 + (-3/5)×1/6 +5/2 =(-3/5)(2/3 ×1/6) + 5/2 = (-3/2)( 2×2+1/6) + 5/2 = -3/2 (5/6) + 5/2 = -1/2 +5/2 = 4/2 = 2 Ans. (ii) = 2/5 × (-3/7) + (1/14 × 2/5) - (1/6 × 3/2) = 2/5 (-3/7 ×1/14) - (1/4)...
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(i) 

-2/3 × 3/5 - 3/5 ×1/6 + 5/2

[ By using commutativity of rational number ]

= (-2/3) × 3/5 + (-3/5)×1/6 +5/2

=(-3/5)(2/3 ×1/6) + 5/2  [Distributive property]

= (-3/2)( 2×2+1/6) + 5/2

= -3/2 (5/6) + 5/2 

= -1/2 +5/2 

= 4/2 = 2   Ans.

(ii) 

= 2/5 × (-3/7) + (1/14 × 2/5) - (1/6 × 3/2)

[By using commutativity of rational number]

= 2/5 (-3/7 ×1/14) - (1/4)   [ By Distributivitily]

= 2/5 (-3×2 +1/ 14 ) - (1/4)

= 2/5 (-6+1/ 14) - (1/4)

= 2/5 (-5/14) - (1/4)

= -1/7 - 1/4

= -4 - 7 / 28

= -11/28    Ans 

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