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Two adjacent angles of a parallelogram have equal measure. Find the measure of each of the angles of the parallelogram.

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Sum of adjacent angles = 180° ∠A + ∠B = 180º 2∠A = 180º (∠A = ∠B) ∠A = 90º ∠B = ∠A = 90º ∠C = ∠A = 90º (Opposite angles) ∠D = ∠B = 90º (Opposite angles) Thus, each angle of the parallelogram measures 90º.
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Sum of adjacent angles = 180°

∠A + ∠B = 180º

2∠A = 180º (∠A = ∠B)

∠A = 90º

∠B = ∠A = 90º

∠C = ∠A = 90º (Opposite angles)

∠D = ∠B = 90º (Opposite angles)

Thus, each angle of the parallelogram measures 90º.

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Engineering graduate from NIT Calicut, Rank holder (#47) in State Entrance Examination.

sum of adjescent angles of parallelogram=180° let one of the adjacent angle = x° x+x=180 2x=180 x=180/2=90° oposite angles are equal to each other hence all 4 angles are 90°
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