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Three consecutive integers add up to 51. What are these integers?

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Engineering graduate from NIT Calicut, Rank holder (#47) in State Entrance Examination.

let the first integer be x. then three consecutive integers are x,x+1,x+2 x+(x+1)+(x+2)=51 3x+3=51 3x=51-3=48 x=48/3=16 so the integers are 16,17,18
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Let three consecutive integers be x, x + 1, and x + 2. Sum of these numbers = x+ x + 1 + x + 2 = 51 3x + 3 = 51 On transposing 3 to R.H.S, we obtain 3x = 51 − 3 3x = 48 On dividing both sides by 3, we obtain x = 16 x + 1 = 17 x + 2 = 18 Hence, the consecutive integers are 16, 17, and 18.
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Let three consecutive integers be x, x + 1, and x + 2.

Sum of these numbers = x+ x + 1 + x + 2 = 51

3x + 3 = 51

On transposing 3 to R.H.S, we obtain

3x = 51 − 3

3x = 48

On dividing both sides by 3, we obtain

x = 16

x + 1 = 17

x + 2 = 18

Hence, the consecutive integers are 16, 17, and 18.

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Comments

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