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Observe the following pattern and find the missing digits.

112 = 121

1012 = 10201

10012 = 1002001

1000012 = 1…2…1

100000012 = …

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In the given pattern, it can be observed that the squares of the given numbers have the same number of zeroes before and after the digit 2 as it was in the original number. Therefore, 1,00,0012 = 10,00,02,00,001 1,00,00,0012 = 10,00,00,02,00,00,001
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