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In a cyclic quadrilateral ABCD, AB = 4, BC= 5, CD = 9 and DA = 5. Find the length of the diagonal AC.
(1) 8
(2) 7
(3) 6
(4) √61.
Solution:
AC*BD = 36+25 = 61
AC/BD = 20+45/ 20+45 = 1
Multiplyin AC^2 = 61
AC = root 61
Formula = AC = √{(ac+bd)×(ad+bc)/(ab+cd)}
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