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The number of all possible matrices of order 3 × 3 with each entry 0 or 1 is:

(A) 27

(B) 18

(C) 81

(D) 512

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The correct answer is D. The given matrix of the order 3 × 3 has 9 elements and each of these elements can be either 0 or 1. Now, each of the 9 elements can be filled in two possible ways. Therefore, by the multiplication principle, the required number of possible matrices is 29 = 512
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The correct answer is D.

The given matrix of the order 3 × 3 has 9 elements and each of these elements can be either 0 or 1.

Now, each of the 9 elements can be filled in two possible ways.

Therefore, by the multiplication principle, the required number of possible matrices is 29 = 512

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Related Questions

If a matrix has 24 elements, what are the possible orders it can have? What, if it has 13 elements?
24 = 1 X 24 = 2 X 12 = 3 X 8 = 4 X 6 = 6 X 4 = 8 X 3 = 12 X 2 = 24 X 1 So, there are 8 orders possible. Similarly 13 = 1 X 13 and 13 X1, So, only 2 orders are possible.
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