I have an experience taking tution over 3 years.
Will make my student to enjoy and understand the basic idea of the subject.
I was taking tution in Adyar, currently, I have been relocated to Velacherry.
I have the passion to teach.
/> Velachery, Chennai, India - 600042.
Details verified of Mahalakshmi S.✕
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Tamil Mother Tongue (Native)
English Proficient
Madras university 2011
Bachelor of Science (B.Sc.)
Velachery, Chennai, India - 600042
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
State, CBSE
Experience in School or College
Home tution
Taught in School or College
Yes
State Syllabus Subjects taught
English, Tamil, Physics, Accountancy, Mathematics, Electronics, Chemistry
Teaching Experience in detail in Class 12 Tuition
I have taken tution at my home for classes 1_12 Maths and science for 3 years. Individual care will be given. Make the student to understand the basics.
1. Which school boards of Class 12 do you teach for?
State and CBSE
2. Have you ever taught in any School or College?
Yes
3. Which classes do you teach?
I teach Class 12 Tuition Class.
4. Do you provide a demo class?
Yes, I provide a paid demo class.
5. How many years of experience do you have?
I have been teaching for 3 years.
Answered on 13/05/2020 Learn CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
((1(1+i)-2(1-4i))/((1-4i)(1+i))*((3-4i)/(5+i))
((1+i-2+8i)/(1+i-4i-4i^2))*((3-4i)/(5+i))
i^2=-1
((-1+9i)/(1-3i+4))*((3-4i)/(5+i))
((-1+9i)/(5-3i))*((3-4i)/(5+i))
(-3+4i+27i-36i^2)/(25+5i-15i-3i^2)
(-3+31i+36)/(25-10i+3)
((33+31i)/(28-10i))((28+10i)/(28+10i))
(924+330i+858i+310i^2)/((28)^2-(10i)^2) [(a+b)(a-b)=a^2-b^2]
(924-310+330i+868i)/(784+100)
(614+1198i)/884
Taking 2 out of the fraction
2(307+599i)/2(442)
(307+599i)/442
(307/442)+(599i/442)
Answered on 13/05/2020 Learn CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
Let z1= x+iy --(1)
z2=a+ib --(2)
Rez1=x --(3) Imz1=y --(5)
Rez2=a --(4) Imz2=b --(6)
From (1&2) z1z2=(x+iy)(a+ib)
=xa+ixb+iya+i^2yb. (i^2=-1)
= xa+ixb+iya-yb
=xa-yb + i(xb+ya)
Re(z1z2)= xa-yb -- LHS
from(3,4,5&6)
Rez1Rez2-Imz1Imz2 = xa-yb --- RHS
LHS = RHS .Hence Proved.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
State, CBSE
Experience in School or College
Home tution
Taught in School or College
Yes
State Syllabus Subjects taught
English, Tamil, Physics, Accountancy, Mathematics, Electronics, Chemistry
Teaching Experience in detail in Class 12 Tuition
I have taken tution at my home for classes 1_12 Maths and science for 3 years. Individual care will be given. Make the student to understand the basics.
Answered on 13/05/2020 Learn CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
((1(1+i)-2(1-4i))/((1-4i)(1+i))*((3-4i)/(5+i))
((1+i-2+8i)/(1+i-4i-4i^2))*((3-4i)/(5+i))
i^2=-1
((-1+9i)/(1-3i+4))*((3-4i)/(5+i))
((-1+9i)/(5-3i))*((3-4i)/(5+i))
(-3+4i+27i-36i^2)/(25+5i-15i-3i^2)
(-3+31i+36)/(25-10i+3)
((33+31i)/(28-10i))((28+10i)/(28+10i))
(924+330i+858i+310i^2)/((28)^2-(10i)^2) [(a+b)(a-b)=a^2-b^2]
(924-310+330i+868i)/(784+100)
(614+1198i)/884
Taking 2 out of the fraction
2(307+599i)/2(442)
(307+599i)/442
(307/442)+(599i/442)
Answered on 13/05/2020 Learn CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
Let z1= x+iy --(1)
z2=a+ib --(2)
Rez1=x --(3) Imz1=y --(5)
Rez2=a --(4) Imz2=b --(6)
From (1&2) z1z2=(x+iy)(a+ib)
=xa+ixb+iya+i^2yb. (i^2=-1)
= xa+ixb+iya-yb
=xa-yb + i(xb+ya)
Re(z1z2)= xa-yb -- LHS
from(3,4,5&6)
Rez1Rez2-Imz1Imz2 = xa-yb --- RHS
LHS = RHS .Hence Proved.
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