UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕
true
Amarjeet Singh Class 11 Tuition trainer in Chandigarh/>

Amarjeet Singh

Engg College, Chandigarh, India - 160012.

Contact
Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Amarjeet Singh✕

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

My experience of working with UNIPROFS has been phenomenal.since first day I feel really happy to help the young minds. As teaching has been something really close to my heart,from the time I really understand #ateacher.
I am pursuing B.Tech in mechanical engineering from the very renowned institute punjab engineering college chandigarh.
i have qualified jee mains and advance with all india rank of 36,000 and 12,600 respectively.
while my preparation i have understood the pros&cons and gained the invaluable experience.

Languages Spoken

Hindi Mother Tongue (Native)

English Basic

Education

PEC university of technology Pursuing

Bachelor of Technology (B.Tech.)

Address

Engg College, Chandigarh, India - 160012

Verified Info

Phone Verified

Email Verified

Report this Profile

✕
x

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Mathematics, Chemistry

Experience in School or College

i have taught students in coaching institutes for preparation of various competetive exams in the last 2 years.

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry, Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

State and CBSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 11 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Contact

Answers by Amarjeet Singh (1)

Answered on 08/06/2020 Learn Tuition

5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z

Solving the above equation: Sum of squares will be zero only if each individual number is zero; Therefore we have: 2x=y, 2y=z, 2z=x x:y:z = x/x :y/x :z/x. = 1:2:1/2 therefore x:y:z = 2:4:1 ...more

Solving the above equation:

Sum of squares will be zero only if each individual number is zero;

Therefore we have: 2x=y, 2y=z, 2z=x

x:y:z = x/x :y/x :z/x.

        = 1:2:1/2

 therefore x:y:z = 2:4:1

Answers 353 Comments
Dislike Bookmark

Contact

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Mathematics, Chemistry

Experience in School or College

i have taught students in coaching institutes for preparation of various competetive exams in the last 2 years.

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry, Mathematics

No Reviews yet!

Answers by Amarjeet Singh (1)

Answered on 08/06/2020 Learn Tuition

5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z

Solving the above equation: Sum of squares will be zero only if each individual number is zero; Therefore we have: 2x=y, 2y=z, 2z=x x:y:z = x/x :y/x :z/x. = 1:2:1/2 therefore x:y:z = 2:4:1 ...more

Solving the above equation:

Sum of squares will be zero only if each individual number is zero;

Therefore we have: 2x=y, 2y=z, 2z=x

x:y:z = x/x :y/x :z/x.

        = 1:2:1/2

 therefore x:y:z = 2:4:1

Answers 353 Comments
Dislike Bookmark

Contact

Amarjeet Singh conducts classes in Class 11 Tuition. Amarjeet is located in Engg College, Chandigarh. Amarjeet takes at students Home and Online Classes- via online medium. He has 2 years of teaching experience . Amarjeet is pursuing Bachelor of Technology (B.Tech.) from PEC university of technology. He is well versed in Hindi and English.

X

Share this Profile

Recommended Profiles

Aahan Kumar

Aahan Kumar photo Engg College, Chandigarh

Shivam Mishra

Shivam Mishra photo Engg College, Chandigarh

Gopal Lal Jat

Gopal Lal Jat photo Engg College, Chandigarh

Shubham Dalia

Shubham Dalia photo Engg College, Chandigarh

Rupinder K.

Rupinder K. photo Engg College, Chandigarh

Pooja P. photo

Pooja P.

Pooja P. photo Engg College, Chandigarh

Also have a look at

Learn More

NCERT Solutions For Class 11 NCERT Solutions for Class 11 English Book 1 - Hornbill Literature Chapter 1 - The Portrait of a Lady Literature Chapter 2 - Were Not Afraid to Die Literature Chapter 3 - Discovering Tut: The Saga Continues Literature Chapter 4 - Landscape of the Soul Literature Chapter 5 - The Ailing Planet: the Green Movements Role Literature Chapter 6 - The Browning Version Literature Chapter 7 - The Adventure Literature Chapter 8 - Silk Road

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

✕

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.

✕

Different batches available for this Course

Book a Free Demo

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2024All Rights Reserved