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Overview

My experience of working with UNIPROFS has been phenomenal.since first day I feel really happy to help the young minds. As teaching has been something really close to my heart,from the time I really understand #ateacher.
I am pursuing B.Tech in mechanical engineering from the very renowned institute punjab engineering college chandigarh.
i have qualified jee mains and advance with all india rank of 36,000 and 12,600 respectively.
while my preparation i have understood the pros&cons and gained the invaluable experience.

Languages Spoken

Hindi Mother Tongue (Native)

English Basic

Education

PEC university of technology Pursuing

Bachelor of Technology (B.Tech.)

Address

Engg College, Chandigarh, India - 160012

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Phone Verified

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, State

CBSE Subjects taught

Mathematics, Chemistry

Experience in School or College

i have taught students in coaching institutes for preparation of various competetive exams in the last 2 years.

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry, Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

CBSE and State

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 11 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Contact

Answers by Amarjeet Singh (1)

Answered on 08/06/2020 Learn Tuition

5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z

Solving the above equation: Sum of squares will be zero only if each individual number is zero; Therefore we have: 2x=y, 2y=z, 2z=x x:y:z = x/x :y/x :z/x. = 1:2:1/2 therefore x:y:z = 2:4:1 ...more

Solving the above equation:

Sum of squares will be zero only if each individual number is zero;

Therefore we have: 2x=y, 2y=z, 2z=x

x:y:z = x/x :y/x :z/x.

        = 1:2:1/2

 therefore x:y:z = 2:4:1

Answers 353 Comments
Dislike Bookmark

Contact

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, State

CBSE Subjects taught

Mathematics, Chemistry

Experience in School or College

i have taught students in coaching institutes for preparation of various competetive exams in the last 2 years.

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry, Mathematics

No Reviews yet!

Answers by Amarjeet Singh (1)

Answered on 08/06/2020 Learn Tuition

5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z

Solving the above equation: Sum of squares will be zero only if each individual number is zero; Therefore we have: 2x=y, 2y=z, 2z=x x:y:z = x/x :y/x :z/x. = 1:2:1/2 therefore x:y:z = 2:4:1 ...more

Solving the above equation:

Sum of squares will be zero only if each individual number is zero;

Therefore we have: 2x=y, 2y=z, 2z=x

x:y:z = x/x :y/x :z/x.

        = 1:2:1/2

 therefore x:y:z = 2:4:1

Answers 353 Comments
Dislike Bookmark

Contact

Amarjeet Singh conducts classes in Class 11 Tuition. Amarjeet is located in Engg College, Chandigarh. Amarjeet takes at students Home and Online Classes- via online medium. He has 2 years of teaching experience . Amarjeet is pursuing Bachelor of Technology (B.Tech.) from PEC university of technology. He is well versed in Hindi and English.

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