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Write a programme to swap two numbers with out using a third variable and by using bitwise op-erators.

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Computer Science Tutor

a=a+b // a*b // a^b b=a-b // a/b // b^a a=a-b // a/b // a^b
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Take a demo class and you will know

/* Swap a and b */ a ^= b ^= a ^= b ;
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main(){ int a=5,b=10; printf("\r\n Before Swap"); printf("\r\na=%d and b=%d",a,b); a^=b^=a^=b; printf("\r\n After Swap"); printf("\r\na=%d and b=%d",a,b); return 0; }
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Technical Corporate Trainer

User XOR ( ^ ) x = x ^ y; y = x ^ y; x = x ^ y;
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One-to-One Computer & Programming Coaching | 14+ Years of Excellence

Hi, Ranjeeth.... It's very simple.. just open the following link... http://includehelp.com/c-programs/c-bitwise-programs-to-swap-two-numbers-using-bitwise-operator.aspx
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a=a^b; b=a^b a=a^b
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Computer Teacher

import java.io.*; class swap{ public static void main(String args) throws IOException{ BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); System.out.print("Enter 1st no: "); int x=Integer.parseInt(br.readLine()); System.out.print("Enter...
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import java.io.*; class swap{ public static void main(String args[]) throws IOException{ BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); System.out.print("Enter 1st no: "); int x=Integer.parseInt(br.readLine()); System.out.print("Enter 2nd no: "); int y=Integer.parseInt(br.readLine()); System.out.println("\nNumbers Before Swapping:"); System.out.println("x = "+x); System.out.println("y = "+y); //Swapping Method 2 x = x^y; y = x^y; x = x^y; System.out.println("\nNumbers After Swapping:"); System.out.println("x = "+x); System.out.println("y = "+y); } } read less
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Expert in ECE skill set.

Int a; Int b; a=a+b; b=a-b; a=a-b; Printf("a=?d b=%d", a,b); ----- take two numbers and check
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a = a-b b = a+b a = b-a
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XOR of 10 (In Binary 1010) and 5 (In Binary 0101) is 1111 and XOR of 7 (0111) and 5 (0101) is (0010).So the code is --------------------------------------- int x = 10, y = 5; x = x ^ y; // x now becomes 15 (1111) y = x ^ y; // y becomes 10 (1010) x = x ^ y; // x becomes 5 (0101)
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