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Overview

I am currently pursuing Btech in Mechanical Engineering from IIT Madras | Chemistry, Physics, Math | AIR-1314 | Can help with competitive exam prep as well

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

IIT Madras Pursuing

Bachelor of Technology (B.Tech.)

Address

Basai Road, Basai Road, India - 122001

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Phone Verified

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

1

Board

International Baccalaureate, CBSE, ISC/ICSE

IB Subjects taught

Physics, Mathematics, Chemistry

ISC/ICSE Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Mathematics, Chemistry, Physics

Experience in School or College

I was a saathi mentor for ug first year. Have taught class 11 syllabus informally, both jee focused and other

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

International Baccalaureate, CBSE, ISC/ICSE

IB Subjects taught

Physics, Mathematics, Chemistry

ISC/ICSE Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Mathematics, Chemistry, Physics

Experience in School or College

Informally

Taught in School or College

Yes

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

International Baccalaureate, CBSE and ISC/ICSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 1 year.

Answers by Manu Chauhan (3)

Answered on 14/08/2020 Learn CBSE/Class 11

We will be applying Integration by Parts, Consider ∫ logx dx = ∫ logx.1 dx where f(x) = logx , g(x) = 1 we know, ∫ f(x) g(x) dx = f(x) ∫ g(x) dx - ∫f'(x) (∫ g(x) dx) dx Applying the above formula we get, ∫ logx.1 dx = logx .x - ∫ 1/x (x) dx +c = xlogx - ∫ dx +c =... ...more

We will be applying Integration by Parts,

Consider ∫ logx dx = ∫ logx.1 dx where f(x) = logx , g(x) = 1 we know, ∫ f(x) g(x) dx =  f(x) ∫ g(x) dx - ∫f'(x) (∫ g(x) dx) dx Applying the above formula we get, ∫ logx.1 dx = logx .x - ∫ 1/x (x) dx +c = xlogx - ∫ dx +c = xlogx - x +c = x(logx -1) +c, Where c is the constanct of Integration.

Answers 218 Comments
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Answered on 14/08/2020 Learn CBSE/Class 11/Science/Chemistry

Ions are the atoms or molecules having a charge on it, which is due to the gain or loss of electrons to form an ionic bond. The ions with opposite charges suffer opposite charge attraction, i.e. the electrostatic attraction and form the compound based on ionic bond. The ions are of two types: Cation:... ...more

Ions are the atoms or molecules having a charge on it, which is due to the gain or loss of electrons to form an ionic bond. The ions with opposite charges suffer opposite charge attraction, i.e. the electrostatic attraction and form the compound based on ionic bond. The ions are of two types: Cation: Positively charged atom, i.e. formed by loss of extra electron in the outermost shell of an atom which is loosely bound or have a least nuclear charge. E.g. Na+, Ca2+, Mg2+, etc.. Anion: Negatively charged atom, i.e. formed by the gain of one or more electron to complete the octet of the outermost shell of the atom. e.g. Cl-, Br-, SO2-, etc.

Answers 186 Comments
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Answered on 14/08/2020 Learn CBSE/Class 11/Science/Physics

Position vector specifies the position of a with object respect to an origin ( chosen as a reference point ). At the same time, the displacement vector is the change in the position vector of two points and is ideally not dependent on the origin. ...more

Position vector specifies the position of a with object respect to an origin ( chosen as a reference point ). At the same time, the displacement vector is the change in the position vector of two points and is ideally not dependent on the origin.

Answers 145 Comments
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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

1

Board

International Baccalaureate, CBSE, ISC/ICSE

IB Subjects taught

Physics, Mathematics, Chemistry

ISC/ICSE Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Mathematics, Chemistry, Physics

Experience in School or College

I was a saathi mentor for ug first year. Have taught class 11 syllabus informally, both jee focused and other

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

International Baccalaureate, CBSE, ISC/ICSE

IB Subjects taught

Physics, Mathematics, Chemistry

ISC/ICSE Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Mathematics, Chemistry, Physics

Experience in School or College

Informally

Taught in School or College

Yes

No Reviews yet!

Answers by Manu Chauhan (3)

Answered on 14/08/2020 Learn CBSE/Class 11

We will be applying Integration by Parts, Consider ∫ logx dx = ∫ logx.1 dx where f(x) = logx , g(x) = 1 we know, ∫ f(x) g(x) dx = f(x) ∫ g(x) dx - ∫f'(x) (∫ g(x) dx) dx Applying the above formula we get, ∫ logx.1 dx = logx .x - ∫ 1/x (x) dx +c = xlogx - ∫ dx +c =... ...more

We will be applying Integration by Parts,

Consider ∫ logx dx = ∫ logx.1 dx where f(x) = logx , g(x) = 1 we know, ∫ f(x) g(x) dx =  f(x) ∫ g(x) dx - ∫f'(x) (∫ g(x) dx) dx Applying the above formula we get, ∫ logx.1 dx = logx .x - ∫ 1/x (x) dx +c = xlogx - ∫ dx +c = xlogx - x +c = x(logx -1) +c, Where c is the constanct of Integration.

Answers 218 Comments
Dislike Bookmark

Answered on 14/08/2020 Learn CBSE/Class 11/Science/Chemistry

Ions are the atoms or molecules having a charge on it, which is due to the gain or loss of electrons to form an ionic bond. The ions with opposite charges suffer opposite charge attraction, i.e. the electrostatic attraction and form the compound based on ionic bond. The ions are of two types: Cation:... ...more

Ions are the atoms or molecules having a charge on it, which is due to the gain or loss of electrons to form an ionic bond. The ions with opposite charges suffer opposite charge attraction, i.e. the electrostatic attraction and form the compound based on ionic bond. The ions are of two types: Cation: Positively charged atom, i.e. formed by loss of extra electron in the outermost shell of an atom which is loosely bound or have a least nuclear charge. E.g. Na+, Ca2+, Mg2+, etc.. Anion: Negatively charged atom, i.e. formed by the gain of one or more electron to complete the octet of the outermost shell of the atom. e.g. Cl-, Br-, SO2-, etc.

Answers 186 Comments
Dislike Bookmark

Answered on 14/08/2020 Learn CBSE/Class 11/Science/Physics

Position vector specifies the position of a with object respect to an origin ( chosen as a reference point ). At the same time, the displacement vector is the change in the position vector of two points and is ideally not dependent on the origin. ...more

Position vector specifies the position of a with object respect to an origin ( chosen as a reference point ). At the same time, the displacement vector is the change in the position vector of two points and is ideally not dependent on the origin.

Answers 145 Comments
Dislike Bookmark

Manu Chauhan conducts classes in Class 11 Tuition and Class 12 Tuition. Manu is located in Basai Road, Basai Road. Manu takes Online Classes- via online medium. He has 1 years of teaching experience . Manu is pursuing Bachelor of Technology (B.Tech.) from IIT Madras. HeĀ is well versed in English and Hindi.

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