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Vikas Kumar Singh Class 12 Tuition trainer in Bangalore

Vikas Kumar Singh

Chandapura, Bangalore, India - 560099.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Vikas Kumar Singh✕

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Education

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Overview

I am engineer having about 10 years experience of teaching in mathematics.
I teach in simple way so that average student also can understand.
From xth to xii level easily I can teach.
Even iit jee students also I am handling.

Languages Spoken

English Proficient

Education

Rcc iit 2012

Bachelor of Technology (B.Tech.)

Address

Chandapura, Bangalore, India - 560099

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Teaches

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

8

Board

IGCSE, State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Physics

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

10

Board

IGCSE, State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Physics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

10

Board

ICSE, CBSE, State, IGCSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

7

Engineering Entrance Exams

IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Advanced Coaching

Type of class

Regular Classes, Crash Course

IIT-JEE Subjects

Maths

Teaching Experience in detail in Engineering Entrance Coaching classes

I have been teaching for class 11th,12th and for IIT jee students.My specialist subject is mathematics. I teach in simple way so that average students also can understand very easily.

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

IGCSE, State, ISC/ICSE and others

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition and Engineering Entrance Coaching Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 8 years.

Contact

Answers by Vikas Kumar Singh (4)

Answered on 12/05/2020 Learn CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5

Find the real numbers x and y if (x – iy) (3 + 5i) is the conjugate of –6 – 24i. ...more
Find the real numbers x and y if (x – iy) (3 + 5i) is the conjugate of –6 – 24i.

(x-iy)(3+5i)=-6+24i 3x-3iy+5ix+5y=-6+24i Equate real and imaginary parts 3x+5y=-6 and 5x-3y=24 after solving this eqution We got X=3 an Y=-3
Answers 5 Comments
Dislike Bookmark

Answered on 07/09/2019 Learn CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.5

Find of function. ...more

Take log both sides and differentiate both sides. That is xlogy=ylogx X/y.dy/dx+logy=y.1/x+logx.dy/dx dy/dx(x/y-logx)=1/x-logy dy/dx=(1/x-logy)/(x/y-logx) dy/dx=y(1-xlogy)/x(x-ylogx)
Answers 2 Comments
Dislike Bookmark

Answered on 03/09/2019 Learn CBSE/Class 12/Mathematics/Matrices/NCERT Solutions/Exercise 3.2

If, find values of x and y. ...more

2x-y=10 and 3x+y=5 Solve these equation we get X=3 and y=-4
Answers 4 Comments
Dislike Bookmark

Answered on 02/09/2019 Learn CBSE/Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.2

is equal to A) B) C) 0 D) ...more
 is equal to A)  B) C) 0 D)  

 

Ans=B Because inverse of negative cot=pi-inverse of cot And sum of same angle of inverse of cot and tan will be pi/2. So answer B is correct
Answers 7 Comments
Dislike Bookmark

Contact

Teaches

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

8

Board

IGCSE, State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Physics

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

10

Board

IGCSE, State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Physics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

10

Board

ICSE, CBSE, State, IGCSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

7

Engineering Entrance Exams

IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Advanced Coaching

Type of class

Regular Classes, Crash Course

IIT-JEE Subjects

Maths

Teaching Experience in detail in Engineering Entrance Coaching classes

I have been teaching for class 11th,12th and for IIT jee students.My specialist subject is mathematics. I teach in simple way so that average students also can understand very easily.

No Reviews yet!

Answers by Vikas Kumar Singh (4)

Answered on 12/05/2020 Learn CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5

Find the real numbers x and y if (x – iy) (3 + 5i) is the conjugate of –6 – 24i. ...more
Find the real numbers x and y if (x – iy) (3 + 5i) is the conjugate of –6 – 24i.

(x-iy)(3+5i)=-6+24i 3x-3iy+5ix+5y=-6+24i Equate real and imaginary parts 3x+5y=-6 and 5x-3y=24 after solving this eqution We got X=3 an Y=-3
Answers 5 Comments
Dislike Bookmark

Answered on 07/09/2019 Learn CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.5

Find of function. ...more

Take log both sides and differentiate both sides. That is xlogy=ylogx X/y.dy/dx+logy=y.1/x+logx.dy/dx dy/dx(x/y-logx)=1/x-logy dy/dx=(1/x-logy)/(x/y-logx) dy/dx=y(1-xlogy)/x(x-ylogx)
Answers 2 Comments
Dislike Bookmark

Answered on 03/09/2019 Learn CBSE/Class 12/Mathematics/Matrices/NCERT Solutions/Exercise 3.2

If, find values of x and y. ...more

2x-y=10 and 3x+y=5 Solve these equation we get X=3 and y=-4
Answers 4 Comments
Dislike Bookmark

Answered on 02/09/2019 Learn CBSE/Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.2

is equal to A) B) C) 0 D) ...more
 is equal to A)  B) C) 0 D)  

 

Ans=B Because inverse of negative cot=pi-inverse of cot And sum of same angle of inverse of cot and tan will be pi/2. So answer B is correct
Answers 7 Comments
Dislike Bookmark

Contact

Vikas Kumar Singh conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Vikas is located in Chandapura, Bangalore. Vikas takes at students Home and Regular Classes- at his Home. He has 10 years of teaching experience . Vikas has completed Bachelor of Technology (B.Tech.) from Rcc iit in 2012. He is well versed in English.

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