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Quest Academy

RT Nagar, Bangalore, India - 560032

19 Students

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Teaches

Engineering Entrance Coaching classes
3 Students

Institute of the month Nov '19

For Engineering Entrance Coaching in Bangalore

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Engineering Entrance Exams

BITSAT Coaching Classes, IIT JEE Coaching Classes

Type of class

Regular Classes, Crash Course

IIT JEE Coaching

IIT JEE Crash Course, IIT JEE Foundation Course, IIT JEE Integrated Coaching, IIT JEE Advanced Coaching, IIT JEE Mains Coaching

IIT-JEE Subjects

Physics , Chemistry , Maths

Class 11 Tuition
3 Students

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE, State

CBSE Subjects taught

Biology, Mathematics, Physics, Chemistry

State Syllabus Subjects taught

Chemistry, Mathematics, Biology, Physics

Class 12 Tuition
3 Students

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE, State

CBSE Subjects taught

Biology, Mathematics, Physics, Chemistry

State Syllabus Subjects taught

Chemistry, Mathematics, Biology, Physics

Medical Entrance Coaching classes
3 Students

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Teaches for following exams

AIIMS Coaching

Type of class

Regular Classes, Crash Course

Class 9 Tuition
3 Students

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Class 10 Tuition
3 Students

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE

CBSE Subjects taught

Mathematics, Science

CET Coaching classes
3 Students

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Subjects

Chemistry, Biology, Mathematics, Physics

Class type catered to

Crash course, Integrated coaching classes, Regular Classes

NEET-UG Coaching Classes
3 Students

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

NEET Subjects

Biology, Chemistry, Physics

4.9 out of 5 16 reviews

Quest Academy https://www.urbanpro.com/assets/new-ui/institute-100X100.png RT Nagar
4.90516
Quest Academy
A

IIT JEE Coaching

"Faculties are excellent. If someone has a path in his/her mind, they will get all the amenities to accomplished it. "

Have you attended any class with Quest Academy?

Answers by Quest Academy (25)

Answered on 04/06/2017 Learn Tuition/Class IX-X Tuition

Newton's second law of motion describes the relationship between an object's mass and the amount of force needed to accelerate it. Newton's second law is often stated as F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)
Answers 183 Comments
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Answered on 04/06/2017 Learn Tuition/Class XI-XII Tuition (PUC)

Value of Tan(360 degree) = 0.0000
Answers 145 Comments
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Answered on 25/06/2016 Learn Tuition/Class XI-XII Tuition (PUC)

The charge on the capacitor is Q = CV = 900 × 1012 F × 100 V = 9 × 108 C The energy stored in the capacitor = (1/2) CV2 = (1/2) QV = (1/2) × 9 × 108 C × 100 V = 4.5 × 10% J
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Answered on 23/06/2016 Learn Tuition/Class IX-X Tuition

Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity ×time ?distance=15.7m/s... ...more
Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity ×time ?distance=15.7m/s ×140 s = 2198 m (b) Displacement after 2 m 20 s i.e. in 140 s Since,rotatin in 40 s=1 Motion Ex3 Therefore, in 3.5 rotations athlete will be just at the opposite side of the circular track, i.e. at a distance equal to the diameter of the circular track which is equal to 200 m. Therefore, Distance covered in 2 m 20 s = 2198 m And, displacement after 2 m 20 s = 200m 2. Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C? Answer:- Motion Ex4 Here we have, Distance from point A to B = 300 m Time taken = 2 minute 30 second = 2 x 60 + 30 s = 150 s Distance from point B to C = 100 m Time taken = 1 minute = 60 s (a) Average speed and velocity from point A to B Motion Ex5 (b) Average speed and velocity from B to C Motion Ex6 Therefore,average velocity=1.66 m/s west
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Quest Academy conducts classes in CET Coaching, Class 10 Tuition and Class 11 Tuition. It is located in RT Nagar, Bangalore. It takes Regular Classes- at the Institute and Online Classes- via online medium. It has got 16 reviews till now with 100% positive feedback.

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