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Anjaneyulu Karusala Engineering Entrance trainer in Bangalore

Anjaneyulu Karusala

Maths Teacher

Brookefield, Bangalore, India - 560037.

Contact
Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Anjaneyulu Karusala✕

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Education

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Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

More than 20 years of teaching experience for XI and XII for all competitive exams like CET/JEE and Board exams.

Languages Spoken

English

Address

Brookefield, Bangalore, India - 560037

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Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

20

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

20

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

CET Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in CET Coaching classes

20

Subjects

Mathematics

Class type catered to

Integrated coaching classes

Reviews

No Reviews yet!

FAQs

1. Which classes do you teach?

I teach CET Coaching, Class 11 Tuition, Class 12 Tuition and Engineering Entrance Coaching Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Contact

Answers by Anjaneyulu Karusala (1)

Answered on 05/12/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

What is the director circle of hyperbola?

The locus of point of intersections of perpendicular tangents to the hyperbola is a circle called as Director circle and for a standard hyperbola (x^2/a^2)-(y^2/b^2)=1, its equation is x^2+y^2 = a^2-b^2.
Answers 4 Comments
Dislike Bookmark

Contact

Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

20

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

20

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

CET Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in CET Coaching classes

20

Subjects

Mathematics

Class type catered to

Integrated coaching classes

No Reviews yet!

Answers by Anjaneyulu Karusala (1)

Answered on 05/12/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

What is the director circle of hyperbola?

The locus of point of intersections of perpendicular tangents to the hyperbola is a circle called as Director circle and for a standard hyperbola (x^2/a^2)-(y^2/b^2)=1, its equation is x^2+y^2 = a^2-b^2.
Answers 4 Comments
Dislike Bookmark

Contact

Anjaneyulu Karusala describes himself as Maths Teacher. He conducts classes in CET Coaching, Class 11 Tuition and Class 12 Tuition. Anjaneyulu is located in Brookefield, Bangalore. Anjaneyulu takes Regular Classes- at his Home and Online Classes- via online medium. He has 20 years of teaching experience . He is well versed in English.

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