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Class 10 > Learn Mathematics > Is there any relation between AM, GM, HM in Progression...
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Is there any relation between AM, GM, HM in Progressions?

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Math magician

Yes relationship is present and also equation is also present
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Qualified (Engg from NIT) & experienced mentor with 6+ yrs experience.

AM×HM=SQR of GM i.e. AM×HM= GM x GM
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Tutor

yes relationship between AM,HM and GM can be shown by this equatiion AM x HM =GM^2
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Best Mathematics Teacher for Weak Students

AM X HM =GM X GM
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Mathematics Expert for CBSE, ICSE, IGCSE, SSC Home & Group Tuition (VI-X)

AH=G2
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bachelor of engineering from Thapar Engineering College, Patiala.

AM × HM = GM Square
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Tutor

If a and b are two numbers such that a,b>0 , then AM of the numbers = (a+b)/2 GM=(ab)^1/2 HM=2/ = 2ab/(a+b) Thus multiplying AM with HM we get AM*HM = * = ab = ^2 = ^2 Thus we get the co-relation as below; GM = ^1/2
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expert group classes

Let there are two numbers ‘a’ and ‘b’, a, b > 0 then AM=a+b/2 GM=?ab HM=2ab/a+b ? AM × HM=a+b/2 × 2ab/a+b = ab=(?ab)2 = (GM)2 And AM>GM>HM
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Dedicated Teacher With Lots of Teaching Experience In Maths For All Boards

AM X HM = GM2(GM square)
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gm=sq rt of am.hm
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