why string class is override in euals()/ hashCode Hethods?

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• In the above program we compared two string using equals() method and it returns true.and comparing using == operator returns false. • Basically equal() will also return false on comparing those two strings because default functionality of equal() method is to compare references and two strings are...
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• In the above program we compared two string using equals() method and it returns true.and comparing using == operator returns false. • Basically equal() will also return false on comparing those two strings because default functionality of equal() method is to compare references and two strings are created using new operator so both references are different. • But String class overriding equals() method and in that equals method it comparing content of the strings and returning true if both are having same content false if not. • Lets see what happen if we compare two stringBuffer objects using equals() method. • package com.instanceofjava; • • class StringBufferEqualsDemo{ • • public static void main(String [] args){ • • StringBuffer fstr= new StringBuffer("Javatutorials"); • StringBuffer sstr= new StringBuffer("Javatutorials"); • • System.out.println(fstr.equals(sstr)); • System.out.println(fstr==sstr); • • System.out.println(fstr.hashCode()); • System.out.println(sstr.hashCode()); • } • } OUTPUT • false • false • 1704856573 • 705927765 • If you observe above java program when we are comparing two stringBuffer objects equal() method returning false even content is same. Because StringBuffer class not overriding equals() and hashcode() methods. • StringBuilder is also not overriding equals() method? lets see a program and clarify. • • package com.instanceofjava; • • class StringBuilderEqualsDemo{ • • public static void main(String [] args){ • • StringBuilder fstr= new StringBuilder("Javatutorials"); • StringBuilder sstr= new StringBuilder("Javatutorials"); • • System.out.println(fstr.equals(sstr)); • System.out.println(fstr==sstr); • • System.out.println(fstr.hashCode()); • System.out.println(sstr.hashCode()); • } • } OUTPUT 1. false 2. false 3. 1704856573 4. 705927765 5. So now its cleared that StringBuffer and StringBuilder classes not overriding equals() and hashCode() methods. 6. But Why? 7. Why StringBuffer and StringBuilder classes not overriding equals() method and hashcode() method where as String class is overriding these two methods. 8. Basically Strings are Immutable means Whenever we try to change the value of string result will be new string. So string content wont change. 9. StringBuffer main use is mutable means when we append a string to it it will add to existing object. 10. When the content changes the hashcode will changes. 11. Lets see a program on adding elements to hashmap. read less
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Bcoz it is method of Object Class & String is final class which extends Object class to override equals & hashcode . equals() method checks whether the content of String is same or not. & hashcode() method returns ref address of it.
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Trainer

By defining equals() and hashCode() consistently, you can improve the usability of your classes as keys in hash-based collections. As the API doc for hashCode explains: "This method is supported for the benefit of hashtables such as those provided by java.util.Hashtable."
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Java developer

Not only string, even wrapper classes also overwritten these 2 methods. To store these immutable objects in a same hashbacket.
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Java Trainer

Equals method and hash code methods compare two objects based the memory location occupied by objects. Two different objects always occupy two different locations in heap memory. So equals and hashCode methods are overriden in string to compare contents of two strings instead of memory location of he...
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Trainer

Equals and hashcode methods are override when we check for object equality or when we want to check and restrict duplicates in hashmap .
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Tutor

Because, In Object class equals method implementation was comparing two objects with '==' operator. That means if two objects(String, or any type) are referring same address location then only true, otherwise it returns false, so in String class they had override the equals and changed the method implementation....
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Because, In Object class equals method implementation was comparing two objects with '==' operator. That means if two objects(String, or any type) are referring same address location then only true, otherwise it returns false, so in String class they had override the equals and changed the method implementation. In current String equal method will check the String value based on that it will return the true/false with irrespective of the memory location. And it was good practice to override hashcode() whenever you override the equals(). hashcode() method was used when object was storing some collections which will follow hashing algorithm(Ex: HashMap, HashSet) For mpre information go through: http://stackoverflow.com/questions/2265503/why-do-i-need-to-override-the-equals-and-hashcode-methods-in-java read less
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Computer professional

to check logical equality of objects
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We may come across the requirement to check for object equality. To check whether both objects contains same properties value or not. This can be done by override the Equals method. While overriding the Equals method, you should consider the followings If object argument is null, return false ...
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We may come across the requirement to check for object equality. To check whether both objects contains same properties value or not. This can be done by override the Equals method. While overriding the Equals method, you should consider the followings If object argument is null, return false If type of object argument is different than type of this, return false If object argument is neither null nor its type is different check for the values of the instance fields. If they are equal return true else return false read less
Comments

Tutor

It is not always necessary to override hash code and equals. But if you think you need to override one, then you need to override both of them
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