Osmania University, Hyderabad, India - 500007.
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Telugu Mother Tongue (Native)
Hindi Basic
English Basic
Chaitanya Bharathi Institute of Technology Pursuing
Bachelor of Engineering (B.E.)
Osmania University Pursuing
Masters of Engineering
Government Polytechnic Masab Tank 2018
Diploma in Civil Engineering
Osmania University, Hyderabad, India - 500007
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Engineering Diploma Branch
Engineering Diploma 1st Year, Civil Engineering Diploma
Engineering Diploma Subject
Communication Skills, Basic Math, English, Engineering Mechanics, Engineering Mathematics, Workshop Drawing, Basic Physics
Civil Engineering Diploma Subject
Transportation Engineering, Mechanics of Structures, Architectural Practices and Interior Design, Surveying, Highway Engineering, Geo Technical Engineering, Theory Of Structures, Irrigation Engineering, Applied Mathematics (CE and ME Group), Building Drawing, Water shade Management, Environment Engineering, Design Of Steel Structures, Building Construction, Estimating & Costing, Computer Aided Drawing, Hydraulics, Micro Irrigation, Design of Structures, Concrete Technology
Type of class
Regular Classes, Crash Course
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
No
1. Which Engineering Diploma branches do you tutor for?
Engineering Diploma 1st Year and Civil Engineering Diploma
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Engineering Diploma Tuition Class.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for less than a year.
Answered on 13/05/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic
Given ratio of present ages P and Q ages is 5:7
Therefore, P = 5x and Q = 7x
Difference of Q present = 7x and
P's age after 6years = 5x+6
is 2
i.e. |7x-5x-6| = 2
=(2x-6) = 2
= 2x-6 =+2, -2
From above eqn x = 4 or x = 2
Sum of present ages of P and Q when x = 4 is 48
Sun of present ages of P and Q when x = 2 is 24
Check :
When x = 4
P = 20 , Q = 28. Sum is 48
Difference is 28-(20+6) = 2 ( hence checked)
When
x = 2
P = 10 and Q = 14.Sum is 24
Difference is (10+6) - 14 = 2 ( Hence checked)
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Engineering Diploma Branch
Engineering Diploma 1st Year, Civil Engineering Diploma
Engineering Diploma Subject
Communication Skills, Basic Math, English, Engineering Mechanics, Engineering Mathematics, Workshop Drawing, Basic Physics
Civil Engineering Diploma Subject
Transportation Engineering, Mechanics of Structures, Architectural Practices and Interior Design, Surveying, Highway Engineering, Geo Technical Engineering, Theory Of Structures, Irrigation Engineering, Applied Mathematics (CE and ME Group), Building Drawing, Water shade Management, Environment Engineering, Design Of Steel Structures, Building Construction, Estimating & Costing, Computer Aided Drawing, Hydraulics, Micro Irrigation, Design of Structures, Concrete Technology
Type of class
Regular Classes, Crash Course
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
No
Answered on 13/05/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic
Given ratio of present ages P and Q ages is 5:7
Therefore, P = 5x and Q = 7x
Difference of Q present = 7x and
P's age after 6years = 5x+6
is 2
i.e. |7x-5x-6| = 2
=(2x-6) = 2
= 2x-6 =+2, -2
From above eqn x = 4 or x = 2
Sum of present ages of P and Q when x = 4 is 48
Sun of present ages of P and Q when x = 2 is 24
Check :
When x = 4
P = 20 , Q = 28. Sum is 48
Difference is 28-(20+6) = 2 ( hence checked)
When
x = 2
P = 10 and Q = 14.Sum is 24
Difference is (10+6) - 14 = 2 ( Hence checked)
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