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Class 9

Class 9 relates to CBSE

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Indrajeet Kumar Sinha Class 9 Tuition trainer in Noida Featured
Sector 1 Greater Noida, Noida
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11 yrs of Exp
350per hour
Classes: Class 9 Tuition, Class 10 Tuition and more.

It was very nice experience to interact with different kind of student who have different way of studying... Simply i was successful to bring out...

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Deepashree Class 9 Tuition trainer in Bangalore Featured
Basaveshwara Nagar, Bangalore
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12 yrs of Exp
500per hour
Classes: Class 9 Tuition, Class 7 Tuition and more.

I have working experience of 2 years teaching for 8th and 9th

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Mukherjee Nagar, Delhi
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Classes: Class 9 Tuition, Class 12 Tuition and more.

I am top Tutor Partner at Urban Pro. Since last 5 years i am conducting classes for Social Sciences and Hindi Language. If you want to Inculcate the...

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Shivam Pandey Class 9 Tuition trainer in Delhi Featured
Laxmi Nagar Vishwakarma Park, Delhi
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6 yrs of Exp
350per hour
Classes: Class 9 Tuition, CUET Coaching and more.

I am working as a teacher in 8, 9, 10 th grade from last 4 years in school, tution and home tutions . My subjests are in 9th is basically maths and...

5
Pragati Chaddha . Class 9 Tuition trainer in Bangalore Featured
Ashok Nagar D' Souza Layout, Bangalore
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6 yrs of Exp
350per hour
Classes: Class 9 Tuition, Class 11 Tuition and more.

I am a teacher , a statistician and a data analyst. I am willing to give online tution to uh in subject maths and statistics. I am a first ranker...

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Sai V. Class 9 Tuition trainer in Madappanahalli Featured
Itagalpura Main Rd, Madappanahalli
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17 yrs of Exp
400per hour
Classes: Class 9 Tuition, Engineering Entrance Coaching and more.

I gained extensive experience in delivering high-quality education following the CBSE/ICSE curriculum. My key responsibilities included: Classroom...

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Pranjal M. Class 9 Tuition trainer in Noida Featured
Sector 4, Noida
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5 yrs of Exp
850per hour
Classes: Class 9 Tuition, Class 7 Tuition and more.

Hello dear students, I am PRANJAL MISHRA, I teach Mathematics (upto A level) . I can improve your understanding in Mathematics using my innovative...

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Virendra M. Class 9 Tuition trainer in Delhi Featured
Sector 5, Dwarka, Delhi
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7 yrs of Exp
500per hour
Classes: Class 9 Tuition, Java Training and more.

I teach Maths and Science to 8th-12th standard students. I have been teaching for 7-8 years. I took classes and batches in different institutions...

9
Jayanagar, Bangalore
Verified
15 yrs of Exp
400per hour
Classes: Class 9 Tuition, Class 6 Tuition and more.

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10
Sasi Priya M. Class 9 Tuition trainer in Chennai Featured
Kolapakkam, Chennai
Verified
10 yrs of Exp
300per hour
Classes: Class 9 Tuition

I'm a maths teacher , worked in , CBSE & State board schools. I have cleared TN Govt's Teachers Eligibility Test . My motto is making children to...

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Class 9 Questions

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Answered on 16 Sep Learn CBSE/Class 9/Mathematics/Geometry/Triangles

Debojit Sarkar

Be the better version of yourself

Let ∠C= x°, ∴ ∠B - x°=18° ⇒ ∠B = 18°+x° ......(i) Again, ∠A - (18°+x°)= 33° ⇒∠A = 33°+18°+x° ......(ii) And ∠A+∠B+∠C =180° ⇒51°+18°+3x°=180° ⇒3x°=(180°-69°) ⇒x°=37° ∴... read more

Let ∠C= x°,

∴ ∠B - x°=18°

⇒ ∠B = 18°+x°  ......(i)

Again, ∠A - (18°+x°)= 33°

⇒∠A = 33°+18°+x° ......(ii) 

And ∠A+∠B+∠C =180°

⇒51°+18°+3x°=180°

⇒3x°=(180°-69°)

⇒x°=37°

∴ ∠C=37°, ∠B= (37+18)=55°, ∠A=(55+33)= 88° [Ans.]

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Answered on 15 Sep Learn CBSE/Class 9/Mathematics/Geometry/Triangles

Debojit Sarkar

Be the better version of yourself

Diagonals of a rectangle bisect each other and they are equal in length ∴Δ AOB will be an isosceles triangle with AO=BO In ΔAOB, ∠AOB = ∠COD ............. ∠OAB=∠OBA ................ ∴∠AOB +2∠OAB = 180° ⇒ 78º + 2∠OAB = 180° ⇒... read more

Diagonals of a rectangle bisect each other and they are equal in length

∴Δ AOB will be an isosceles triangle with AO=BO

In ΔAOB,

∠AOB = ∠COD .............[ Vertically opposite angles]

∠OAB=∠OBA ................[ Angle opposite to equal sides]

∴∠AOB +2∠OAB = 180°

⇒ 78º + 2∠OAB = 180°

⇒ ∠OAB = 51° [ Ans.]

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Answered on 15 Sep Learn CBSE/Class 9/Mathematics/Geometry/Triangles

Debojit Sarkar

Be the better version of yourself

Let the smaller angle is x°, the larger angle will be 2x°, ∴ 3x°= 180° ⇒x° = 60° ∴ smaller angle is 60° and larger angle is 120°
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