0Method 1:
Let AB = a
AC = a
BC = 20-2a
Angle A = 120
Cos 30 = (20-2a)/a
√3/2 = 20-2a/a
a√3 = 40-4a
a( √3 +4) = 40
a = 40/(√3+4)
Method 2:
A = b/√3
B(2+√3) = 20
B = 20/(2+√3)
B = 20(2-√3)
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Method 1:
Let AB = a
AC = a
BC = 20-2a
Angle A = 120
Cos 30 = (20-2a)/a
√3/2 = 20-2a/a
a√3 = 40-4a
a( √3 +4) = 40
a = 40/(√3+4)
Method 2:
A = b/√3
B(2+√3) = 20
B = 20/(2+√3)
B = 20(2-√3)
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