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(a) What is the total capacitance of the combination?
(b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?
Asked by Pratik Last Modified
Answer 
Apoorva Purohit
(a) Capacitance of each of the three capacitors, C = 9 pF
Equivalent capacitance (C’) of the combination of the capacitors is given by the relation,
1C'=1C+1C+1C⇒1C'=19+19+19=13⇒C'=3 pF
Therefore, total capacitance of the combination is 3 pF
.
(b) Supply voltage, V = 120 V
Potential difference (V') across each capacitor is equal to one-third of the supply voltage.
Therefore, the potential difference across each capacitor is 40 V.
read less Shivank Sharma
Engineer and a civil services exam aspirant.
The capacitance of each of three capacitors =9pf
(a) equivalent capacitance= C'
1/C'= 1/C1 + 1/C2 + 1/C3
= 1/9 + 1/9 + 1/9
1/C' = 3/9
C' = 3pf
(b) supply voltage (V)=120V
potential difference across each capacitor is 1/3rd of supply voltage.
i.e. V'= V/3
V' = 120/3
V' = 40 volts
V' = 40 volts
read less P Rahul Rahul
POST GRADUATE IN EEE, NOT HAVING EXPERIENCE IN TEACHING BUT HAVE EXPERIENCE IN PROBLEM SOLVING
a) Answer is 3pf because as the capacitors are connected in series. The formula is when there are 'n' identical capacitors each are having m' farads. Then the shortcut answer is m/n.for detailed explanation I will tell u when we come across together in sharing of knowledge
(b). the Answer is 40v.as the capacitors are identical and are in series the voltage across them will divide equally.
(b). answer is 40v.as the capacitors are identical and are in series the voltage across them will divide equally.
read less Gourab Saha
Clear Your Concepts and Score Higher
The capacitance of each of three capacitors =9pf(a) equivalent capacitance(C')
1/C'= 1/C1 + 1/C2 + 1/C3 = 1/9 + 1/9 + 1/9
1/C' = 3/9
C' = 3pf
(b) supply voltage (V)=120Vpotential difference across each capacitor is 1/3rd of supply voltage.i.e. V'= V/3
V' = 120/3
V' = 40 volts
V' = 40 volt
Given, C1 = C2 = C3 = 9 pF = 9 x 10-12 F
V = 120 volt
a) Total capacitance of the series combination is given by
⇒ 
⇒ 
Cnet = 3 x 10-12 F = 3 pico-Farad.
(b) Let q be the charge on each capacitor.
Sum of the potential difference across the plates of the three capacitors must be equal to 120 V
⇒ V1 + V2 + V3 = Vnet
⇒ 
(∵ Vnet = 120 V)
⇒ 
⇒ 
⇒ q = 360 x 10-12 C
Therefore, potential difference across a capacitor
read less
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