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Which line given by its equation: [2 (3x - 2)] - 3 = 7?

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6x=14
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Related Questions

Find three numbers in A.P. whose sum is 21 and their product is 231.
Let, three numbers are (a-d), a, (a+d) So, (a-d)+a+(a+d)=21 => a=7 Again, (7-d)×7×(7+d)=231 => (7-d)×(7+d)=231÷7 => 7^2 - d^2 = 33=> d^2 = 49 - 33=> d^2 = 16=> d = 4 So, the numbers are 7-4= 3, 7 and 7+4=11
Laxmi
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Why is it necessary to take tuition for the 9th and 11th classes?
9th and 11th is the base for 10th and 12th and it's also a continuation... We need to study the base properly then only we can claim 10th and 12th without any disturbance of unknown..
Sandhya
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Find the sum of: 5 + x - (square of x), 3x + 5 + 2(square of x)?
5+x-x² & 3x+5+2x² write the like terms in order, (5+5)+(x+3x)+(-x²+2x²)=10+4x+x²
Divya
Find the solution of the pair of equations: x / 10 + y / 5 - 1 = 0 and x / 8 + y / 6 = 15?
First equation can be changed to x+2y-10 = 0 and second equation can be changed to 3x+4y-360 = 0 multiplying first equation by 4 we get 2x+4y -20 = 0 and subtracting this equation from second equation...
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If the zeroes of the polynomial f(x) = x3 – 12x2 + 39x + a are in AP, find the value of a.
Let p-1,p,p+1 be the roots of given polynomial Now p-1+p+p+1=-b/a1 (P-1)p(p+1)=-d/a1 Compare given polynomial with a1x^3+bx^2+cx+d=0 We get a1=1, b=-12, c=39, d=a 3p=-(-12) P=12/3=4 Therefore (4-1), 4,...
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X Algebra (Maharashtra board 2020)
Solve √(x/y)= 4 (1/x)+(1/y)= 1/(xy) Solution √(x/y)=4 Squaring both sides x/y=16 x=16y x-16y=0 <-eqn1 (1/x)+(1/y)=1/(xy) ((y+x)/xy)=(1/xy) x+y=1 <-eqn2 Multiply by 16 16x+16y=16...

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Try to get the logic behind the problem dont ever waste the time by thinking about answer
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