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Find the roots of the following quadratic equations by factorisation:
Asked by Puneethkumar Last Modified
Answer (i) x² - 3x - 10 = 0 or x² - 5x + 2x - 10 = 0
or x (x - 5) + 2 (x - 5) = 0
or (x + 2) (x - 5) = 0 x = - 2 & x= + 5
(ii) √2x² + 7x + 5√2 = 0
or √2x² + 2x + 5x + 5√2 = 0
or √2x(x + √2) + 5(x + √2) = 0
or (√2x + 5) (x + √2) = 0
x = -5/√2 & -√2
(iii) 2x² + x - 6 = 0 or 2x² + 4x - 3x - 6 = 0
or 2x(x + 2) - 3(x + 2) = 0
or (2x - 3) (x + 2) = 0
x = 3/2 & -2
(iv) 2x² - x + 1/8 = 0 or 16x² - 8x + 1 = 0
or (4x - 1) (4x - 1) = 0
x = 1/4 & 1/4
(v) 100x² - 20x + 1 = 0
or (10x - 1) (10x - 1) = 0
x = 1/10 & 1/10
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Shravan Kumar Prajapati
Maths Tutor
Yashaswi Bomma
mathematics and science professional tutor with 4 years of experience in home tuitions
Yashaswi Bomma
mathematics and science professional tutor with 4 years of experience in home tuitions
1. X² -5x+2x-10=0
x(x-5) +2(x-5) =0
(X+2) (x-5) =0
X=-2, 5
2. √2x²+5x+2x+5√2=0
X(√2x+5) +√2(√2x+5) =0
(X+√2) (√2x+5) =0
X=-√2, -5/√2
3. 2x²+4x-3x-6=0
2x(x+2) -3(x+2) =0
(2x-3) (x+2) =0
X=3/2, -2
5. (10x)²-2.(10x)(1)+1²=0
(10x-1)² =0
X=±1/10
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