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Asked by Raju Last Modified
Answer 
To calculate 6 raised to the power of 13 in C language, you can use a loop or the pow() function from the math library. The pow() function accepts two arguments: the base and the exponent, and returns the result of raising the base to the exponent. Here's a simple example:
#include <stdio.h>
#include <math.h>
int main()
{
double result = pow(6, 13);
printf("6 raised to the power of 13 is: %lf\n", result); return 0;
}
read less #include <stdio.h>
#include <math.h>
int main() {
int base = 6;
int exponent = 13;
// Using loop
long long result = 1;
for(int i = 0; i < exponent; i++) {
result *= base;
}
printf("Result using loop: %lld\n", result);
// Using pow() function
double powered_result = pow(base, exponent);
printf("Result using pow() function: %.0f\n", powered_result);
return 0;
}
In the C programming language, you can calculate the power of a number using the pow() function from the <math.h> library. To find 6 raised to the power of 13, you would write a C program that includes the necessary header file and then use the pow() function.
#include <stdio.h>
#include <math.h>
int main() {
double result = pow(6, 13);
printf("6^13 = %.0f\n", result);
return 0;
}
In this example, pow(6, 13) calculates 6 raised to the power of 13, and the result is stored in the result variable. The printf() function then prints the result to the console. Note that the %.0f format specifier is used to display the result as an integer, as raising 6 to the power of 13 results in a whole number.
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